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  • #373204
    Nzeribe Nympha
    Participant

    1) A gas thermometer measures temperature by measuring the pressure of a gas inside the fixed volume container. A thermometer reads a pressure of 248 torr at 0.0°C. What is the temperature when the thermometer reads a pressure of 345 torr?

    2) Calculate the final pressure inside a scuba tank after it cools from 1000°C to 25°C. The initial pressure in the tank is 130.0 atm.

    3) Use Gay-Lussac’s law to explain what is wrong with the following statement: “I brought a fully inflated beach ball outside to play volleyball in the snow with my friends, but it exploded before we could start.”

    4) The gas pressure in an aerosol can is 151.6 kPa at 25.0°C, what would the pressure be inside the can at 300.0°C?

    #373230
    Godwin Emmanuel
    Keymaster

    Here is the solution

    1) A gas thermometer measures temperature by measuring the pressure of a gas inside the fixed volume container. A thermometer reads a pressure of 248 torr at 0.0°C. What is the temperature when the thermometer reads a pressure of 345 torr?

    Answer
    P1 = 248Kpa
    T1 = 00c = 0 + 273 = 273 K
    P2 = 345kpa
    T2 =?
    P1/T1 = P2/T2
    248/273= 345/T2
    T2= (273*345)/248
    T2 = 379.8K

    2. Calculate the final pressure inside a scuba tank after it cools from 1000°C to 25°C. The initial pressure in the tank is 130.0 atm.

    Answer
    Kelvin temperature should be used in solving gas laws.
    Kelvin = degree celsius + 273.15
    Kelvin = 25.0°C + 273.15 = 298.15 K
    Convert 1000 °C to Kelvin
    Kelvin = 1000 °C + 273.15 = 1273.15 K

    Given Data:
    P1 (initial pressure) = 130.0 atm
    T1 (initial temperature) = 1000 °C or 1273.15 K
    P2 (final pressure) = unknown?
    T2 (final temperature) = 25.0°C or 298.15 K
    This problem can be solve using Gay-Lussac’s Law with the formula
    P1/T1 =P1/T2 And to solve for P2, we can use P2 = (P1* T2)/T1
    P2 =( 130.0 atm × 298.15 K)/(1273.15 K ) (cancel the unit kelvin)
    P2 = ( 38759.5 atm)/(1273.15 K)
    P2 = 30.44 atm

    3) Use Gay-Lussac’s law to explain what is wrong with the following statement: “I brought a fully inflated beach ball outside to play volleyball in the snow with my friends, but it exploded before we could start.”

    Answer
    This statement is incorrect because according to Gay-Lussac’s law, when You decrease the temperature of a set amount of gas in a container of a fixed volume, the pressure will decrease. The beach ball is at room temperature, therefore when it goes out into the snow, the temperature of the beach ball and the air inside it will decrease.

    4) The gas pressure in an aerosol can is 151.6 kPa at 25.0°C, what would the pressure be inside the can at 300.0°C?

    Answer
    P1/T1 =P1/T2 ( T must be in K)
    25.0°C = 298K
    300.0°C = 573K
    151.6/298=P_2/573
    P2 = (151.6 * 573)/298
    P2 = 391.5kPa

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