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Please Guys help me solve the following chemistry Question

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  • #372904
    Godwin Godson
    Participant

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    1. 568 cm3 of chlorine at 25°C will occupy what volume at -25°C while the pressure remains constant?
    2. A sample of nitrogen now occupies a volume of 250 mL at 25°C. What volume did it occupy at 95°C?
    3. Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.30 L. To what temperature should it be raised to occupy a volume of 6.50 L?
    4. Hydrogen gas was cooled from 150°C to 50°C. Its new volume is 75.0 mL. What was its original volume?
    5. A sample of neon gas at 50°C and with a volume of 2.50 L is cooled from 25°C. What was its original volume?

    #372906
    Godwin Emmanuel
    Keymaster

    Below are solutions for the above solutions

    1) 568 cm3 of chlorine at 25°C will occupy what volume at -25°C while the pressure remains constant?
    Answer
    Convert temperature to Kelvin
    T1 = 25°C = 25 + 273.15 = 298.15
    T2 = -25°C = -25 + 273.15 = 248.15
    V1 = 568 cm3
    V2 = ?
    V1T2=V2T1
    568 * 248.15 = V2 * 298.15
    V2 = (568*248.15)/298.15
    V2 = 472.745 cm3

    2) A sample of nitrogen now occupies a volume of 250 mL at 25°C. What volume did it occupy at 95°C?
    Answer
    Convert temperature to Kelvin
    T1 = 25°C = 25 + 273.15 = 298.15
    T2 = 95°C = 95 + 273.15 = 368.15
    V1 = 250 mL
    V2 = ?
    V1T2=V2T1
    250 * 368.15 = V2 * 298.15
    V2 = (250 * 368.15)/298.15
    V2 = 308.695 mL

    3) Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.30 L. To what temperature should it be raised to occupy a volume of 6.50 L?
    Answer
    Convert temperature to Kelvin
    T1 = 40°C = 40 + 273.15 = 313.15
    T2 = ?
    V1 = 2.30 mL
    V2 = 6.5
    V1T2=V2T1
    2.3 * T2 = 6.5 * 313.15
    T2 = (6.5 * 313.15)/2.3
    T2 = 884.989 L

    4) Hydrogen gas was cooled from 150°C to 50°C. Its new volume is 75.0 mL. What was its original volume?
    Answer
    Convert temperature to Kelvin
    T1 = 150°C = 150 + 273.15 = 423.15
    T2 = 50°C = 50 + 273.15 = 323.15
    V1 = ?
    V2 = 75 mL
    V1T2=V2T1
    V1 * 323.15 = 75 * 423.15
    V1 = (75 * 423.15)/(323.15 )
    V1 = 98.2 mL

    4) A sample of neon gas at 50°C and with a volume of 2.50 L is cooled from 25°C. What was its original volume?
    Answer
    Convert temperature to Kelvin
    T1 = 25°C = 25 + 273.15 = 298.15
    T2 = 50°C = 50 + 273.15 = 323.15
    V1 = ?
    V2 = 2.5 L
    V1T2=V2T1
    V1 * 323.15 = 2.5 * 298.15
    V1 = (2.5 * 298.15)/323.15
    V1 = 2.3065 L

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